0.2313x^2+2.6x-49.83=0

Solution for 0.2313x^2+2.6x-49.83=0 equation:

0.2313x^2+2.6x-49.83=0

a = 0.2313; b = 2.6; c = -49.83;
Δ = b2-4ac
Δ = 2.62-4·0.2313·(-49.83)
Δ = 52.862716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.6)-\sqrt{52.862716}}{2*0.2313}=\frac{-2.6-\sqrt{52.862716}}{0.4626}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.6)+\sqrt{52.862716}}{2*0.2313}=\frac{-2.6+\sqrt{52.862716}}{0.4626}
$